Let f(x)=x^2+10x+29 .What is the minimum value of the function?Enter your answer in the box.
Accepted Solution
A:
Answer:4Step-by-step explanation:givenf(x) = x² + 10x + 29Since the coefficient of the x² term > 0, f(x) will have a minimum valueUse the method of completing the squareadd/ subtract ( half the coefficient of the x- term )² to x² + 10xf(x) = x² + 2(+ 5)x + (5)² - (5)² + 29 = (x + 5)² - 25 + 29 = (x + 5)² + 4When x = - 5 , f(x) has a minimum value at + 4