What is distance between line 12x+35y+5=0 and point (2,0).
Accepted Solution
A:
Answer:29 / 37Step-by-step explanation:The distance between a point (p, q) and a line ax + by + c = 0 is:d = | ap + bq + c | / √(a² + b²)Here, a = 12, b = 35, c = 5, p = 2, and q = 0.d = | (12)(2) + (35)(0) + 5 | / √(12² + 35²)d = 29 / 37