Which polynomials are listed with their correct additive inverse? Check all that apply. x2 + 3x – 2; –x2 – 3x + 2 –y7 – 10; –y7 + 10 6z5 + 6z5 – 6z4; (–6z5) + (–6z5) + 6z4 x – 1; 1 – x (–5x2) + (–2x) + (–10); 5x2 – 2x + 10

we know thatIf two numbers have a sum of zero, then we say they are additive inversessocase A) [tex]x^{2} +3x-2[/tex][tex]-x^{2} -3x+2[/tex]Sum the polynomials[tex](x^{2} +3x-2)+(-x^{2} -3x+2)=0[/tex] therefore they are additive inversescase B) [tex]-y^{7} -10[/tex][tex]-y^{7} +10[/tex]Sum the polynomials[tex](-y^{7} -10)+(-y^{7} +10)=-2y^{7}[/tex] [tex]-2y^{7}\neq 0[/tex]thereforethey are not additive inversescase C) [tex]6z^{5} +6z^{5}-6z^{4}[/tex] [tex](-6z^{5}) +(-6z^{5})+6z^{4}[/tex]Sum the polynomials[tex](6z^{5} +6z^{5}-6z^{4})+((-6z^{5}) +(-6z^{5})+6z^{4})=0[/tex] therefore they are additive inversescase D) [tex]x-1[/tex][tex]1-x[/tex]Sum the polynomials[tex](x-1)+(1-x)=0[/tex] thereforethey are additive inversescase E) [tex](-5x^{2})+(-2x)+(-10)[/tex][tex]5x^{2}-2x+10[/tex]Sum the polynomials[tex]((-5x^{2})+(-2x)+(-10))+(5x^{2}-2x+10)=-4x[/tex] [tex]-4x}\neq 0[/tex]thereforethey are not additive inverses